A dipole with dipole moment 3-60 nC-m is oriented at 60- to an electric field of magnitude 4 - 109 N-C- how much work is required to rotate the dipole until it is antiparallel to field-

Potential energy of a dipole at an angle θ with electric field U = p. E = pE cos θ To rotate the dipole (slowly), we need to work on dipole so that the pote ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Physics

Potential Energy of a Dipole in Uniform Electric Field

A dipole with...

Question

A dipole with dipole moment $3.60 n C - m$ is oriented at $60^{\circ}$ to an electric field of magnitude $4 \times 10^{9} N / C$ , how much work is required to rotate the dipole until it is antiparallel to field.

21.6 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3.6 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

14.4 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7.2 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $21.6 J$
Potential energy of a dipole at an angle $θ$ with electric field
$U = - \to p . \to E = - p E c o s θ$
To rotate the dipole (slowly), we need to work on dipole so that the potential energy is increased. $W = Δ U = U_{f} - U_{i}$
$U_{i} = - p E c o s 60 = - \frac{p E}{2}$
$U_{f} = - p E c o s 180 = + p E$
$W = p E - (- \frac{p E}{2}) = \frac{3 p E}{2}$
$= \frac{3}{2} \times 3.6 \times 10^{- 9} \times 4 \times 10^{9}$
$= 3 \times 3.6 \times 2 = 7.2 \times 3 = 21.6 J$

Suggest Corrections

Similar questions

Q. A dipole with dipole moment

3.60 n C - m

is oriented at

60^{\circ}

to an electric field of magnitude

4 \times 10^{9} N / C

, how much work is required to rotate the dipole until it is antiparallel to field.

Q. A dipole with dipole moment

3.60 n C - m

is oriented at

60^{\circ}

to an electric field of magnitude

4 \times 10^{9} N / C

, how much work is required to rotate the dipole until it is antiparallel to field.

A molecule with dipole moment ‘p’ is placed in an electric field of strength E. Initially the dipole is aligned parallel to the field. If the dipole is to be rotated to be antiparallel to the field, the work required to be done by an external agency is:

Q. An electric dipole of dipole moment

P

is placed parallel to a uniform electric field of magnitude

E .

The amount of work done in slowly rotating the dipole by

60^{\circ}

will be

[

0.77 Mark

]

An electric dipole with dipole moment $4 \times 10^{- 9}$ C m is aligned at $30^{\circ}$ with the direction of a uniform electric field of magnitude $5 \times 10^{4} N C^{- 1}$ . Calculate the magnitude of the torque acting on the dipole.

Join BYJU'S Learning Program

A dipole with dipole moment 3.60 nC−m is oriented at 60∘ to an electric field of magnitude 4×109 N/C, how much work is required to rotate the dipole until it is antiparallel to field.

A dipole with dipole moment $3.60 n C - m$ is oriented at $60^{\circ}$ to an electric field of magnitude $4 \times 10^{9} N / C$ , how much work is required to rotate the dipole until it is antiparallel to field.