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Question

A direct current deposits $$54\ g$$ of silver (Atomic mass $$= 108$$) during electrolysis. How much aluminium (Atomic mass $$= 27$$) would be deposited from aluminium chloride solution by the same amount of electricity?


A
4.5 g
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B
5.4 g
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C
54 g
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D
27 g
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Solution

The correct option is A $$4.5\ g$$
Equivalent mass of silver $$= 108$$

Equivalent mass of aluminium in $$(AlCl_{3}) = \dfrac {27}{3} = 9$$

$$\dfrac {W_{Ag}}{W_{Al}} = \dfrac {E_{Ag}}{E_{Al}}$$

$$\dfrac {54}{W_{Al}} = \dfrac {108}{9}$$

$$W_{Al} = 4.5\ g$$.

Hence, the correct option is $$\text{A}$$

Chemistry

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