A direct current of 5A is superimposed on an alternating current I=10sinωt flowing through a wire. The effective value of the resulting current will be
A
(15/2)A
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B
5√3A
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C
5√5A
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D
15A
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Solution
The correct option is C5√3A effective value of dc current =5A effective value of ac current=10/√2A effective value of resulting current = √I2dc+I2ac=√52+1002/2=5√3A