Question

A disc has a mass of 10 kg distribute uniformly and has a radius of 2 m. Moment of inertia about an axis passing through its centre and perpendicular to its plane is.

• A. 20 $kg{m}^2$
• B. 10 $kg{m}^2$
• C. 40 $kg{m}^2$
• D. 40 $kg{m}^2$

Answer 1

The correct option is A 20 $kg{m}^2$

M.I. of disc = $\frac{m{R}^2}{2}$
Given, m = 10 kg
r = 2 m
M.I. of disc = $\frac{10\times 2^2}{2}$ = 20 $kg{m}^2$