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Standard XII

Physics

Forced Oscillations

A disc is hin...

Question

A disc is hinged in a vertical plane about a point on its radius. What will be the distance of the hinge from the disc centre so that the hinge from the disc centre so that the period a small oscillations under gravity is minimum?

\frac{R}{\sqrt{2}}

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\frac{R}{2}

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\frac{R}{4}

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R

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Solution

The correct option is A $\frac{R}{\sqrt{2}}$
For minimum time period $,$
$d = k$ $[$ where $k$ is radius of gyration about centre of mass $]$
$d = \frac{R}{\sqrt{2}}$
Hence,
option $(A)$ is correct answer.

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A disc is hinged in a vertical plane about a point on its radius. What will be the distance of the hinge from the disc centre so that the hinge from the disc centre so that the period a small oscillations under gravity is minimum?

The correct option is A R√2For minimum time period,d=k [ where k is radius of gyration about centre of mass ]d=R√2Hence,option (A) is correct answer.

The correct option is A $\frac{R}{\sqrt{2}}$
For minimum time period $,$
$d = k$ $[$ where $k$ is radius of gyration about centre of mass $]$
$d = \frac{R}{\sqrt{2}}$
Hence,
option $(A)$ is correct answer.