You visited us 3 times! Enjoying our articles? Unlock Full Access!

Inverse of a Matrix

A disc is rol...

Question

A disc is rolling (without slipping) on a horizontal surface. $C$ is its centre and $Q$ and $P$ are two points equidistant from $C$ . Let $V_{p}, V_{q}$ and $V_{c}$ be the magnitude of velocities of points $P, Q$ and $C$ respectively, then

V_{Q} > V_{C} > V_{P}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

V_{Q} < V_{C} < V_{P}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

V_{Q} = V_{P}, V_{C} = \frac{1}{2} V_{P}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

V_{Q} < V_{C} > V_{P}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $V_{Q} > V_{C} > V_{P}$
From Fig. $(I)$ , we have $O C = r (r a d i u s)$
Therefore, $v = r ω$
Since, $ω = c o n s t a n t$ , therefore $v α r$
Now, form Fig $(I I)$ , it is clear that the distance, $O P < O C < O Q \Rightarrow V_{P} < V_{C} < V_{Q}$ or $V_{Q} > V_{C} > V_{P}$ .

Suggest Corrections

Similar questions

Q. A disc of radius

R

is rolling (without slipping) on a frictionless surface as shown in figure.

C

is it's centre and

Q

and

P

are two points equidistant from

C

. Let

v_{P}, v_{Q}

and

v_{C}

be the magnitudes of velocities of points

P

Q

and

C

respectively, then

Q. A disc is rolling (without slipping) on a horizontal surface.

C

is its centre and

Q

and

P

are two points equidistant from

C

as shown in figure. Let

v_{P}, v_{Q}

and

v_{C}

be the magnitude of velocities of points

P, Q

and

C

respectively, then

A disc is rolling (without slipping) on a horizontal surface. C is its centre and Q and P are two points equidistant from C. Let $v_{P}, v_{Q} a n d v_{C}$ be the magnitude of velocities of points P,Q and C respectively, then

Q. A disc is rolling without slipping on a horizontal surface.

P

and

Q

are two points equidistant from

C

. Then, identify the correct statement regarding the velocity of the points:

Q. A disc is rolling without slipping on a horizontal surface with C, as its centre, and Q and P the two points equidistant from
C. Let

v_{P}, v_{Q}

and

v_{C}

be the magnitudes of velocities of points

P

Q

and

C

respectively, then

Join BYJU'S Learning Program

A disc is rolling (without slipping) on a horizontal surface. C is its centre and Q and P are two points equidistant from C. Let Vp,Vq and Vc be the magnitude of velocities of points P,Q and C respectively, then

The correct option is C VQ>VC>VPFrom Fig. (I), we have OC=r(radius)Therefore, v=rωSince, ω=constant, therefore vαrNow, form Fig (II), it is clear that the distance, OP<OC<OQ⇒VP<VC<VQ or VQ>VC>VP.

A disc is rolling (without slipping) on a horizontal surface. $C$ is its centre and $Q$ and $P$ are two points equidistant from $C$ . Let $V_{p}, V_{q}$ and $V_{c}$ be the magnitude of velocities of points $P, Q$ and $C$ respectively, then