You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Work Energy Theorem

A disc is rol...

Question

A disc is rolling without slipping on a horizontal surface with C, as its centre, and Q and P the two points equidistant from
C. Let $v_{P}, v_{Q}$ and $v_{C}$ be the magnitudes of velocities of points $P$ , $Q$ and $C$ respectively, then

v_{Q} > v_{C} > v_{P}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

v_{Q} < v_{C} < v_{P}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

v_{Q} = v_{P}, v_{C} = \frac{1}{2} v_{P}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

v_{Q} < v_{C} > v_{P}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $v_{Q} > v_{C} > v_{P}$
We can take the point in contact with the ground as instantaneous axis of rotation.
$v = r ω$ or
$v \propto r$
$r_{Q} > r_{C} > r_{P}$
$∵ v_{Q} > v_{C} > v_{P}$ .

Suggest Corrections

Similar questions

Q. A disc is rolling (without slipping) on a horizontal surface.

C

is its centre and

Q

and

P

are two points equidistant from

C

. Let

V_{p}, V_{q}

and

V_{c}

be the magnitude of velocities of points

P, Q

and

C

respectively, then

Q. A disc is rolling (without slipping) on a horizontal surface.

C

is its centre and

Q

and

P

are two points equidistant from

C

as shown in figure. Let

v_{P}, v_{Q}

and

v_{C}

be the magnitude of velocities of points

P, Q

and

C

respectively, then

A disc is rolling (without slipping) on a horizontal surface. C is its centre and Q and P are two points equidistant from C. Let $v_{P}, v_{Q} a n d v_{C}$ be the magnitude of velocities of points P,Q and C respectively, then

Q. A disc is rolling (without slipping) on a horizontal surface.

C

is its centre and

Q

and

P

are two points equidistant from

C

as shown in figure. Let

v_{P}, v_{Q}

and

v_{C}

be the magnitude of velocities of points

P, Q

and

C

respectively, then

Q. A disc of radius

R

is rolling (without slipping) on a frictionless surface as shown in figure.

C

is it's centre and

Q

and

P

are two points equidistant from

C

. Let

v_{P}, v_{Q}

and

v_{C}

be the magnitudes of velocities of points

P

Q

and

C

respectively, then

Join BYJU'S Learning Program

A disc is rolling without slipping on a horizontal surface with C, as its centre, and Q and P the two points equidistant from C. Let vP,vQ and vC be the magnitudes of velocities of points P, Q and C respectively, then

The correct option is A vQ>vC>vPWe can take the point in contact with the ground as instantaneous axis of rotation. v=r ω or v∝r rQ>rC>rP ∵vQ>vC>vP.

A disc is rolling without slipping on a horizontal surface with C, as its centre, and Q and P the two points equidistant from
C. Let $v_{P}, v_{Q}$ and $v_{C}$ be the magnitudes of velocities of points $P$ , $Q$ and $C$ respectively, then

The correct option is A $v_{Q} > v_{C} > v_{P}$
We can take the point in contact with the ground as instantaneous axis of rotation.
$v = r ω$ or
$v \propto r$
$r_{Q} > r_{C} > r_{P}$
$∵ v_{Q} > v_{C} > v_{P}$ .