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Byju's Answer

Standard XII

Physics

Work Energy Theorem

A disc is rol...

Question

A disc is rolling without slipping on a horizontal surface with C, as its centre, and Q and P the two points equidistant from
C. Let $v_{P}, v_{Q}$ and $v_{C}$ be the magnitudes of velocities of points $P$ , $Q$ and $C$ respectively, then

v_{Q} > v_{C} > v_{P}

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v_{Q} < v_{C} < v_{P}

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v_{Q} = v_{P}, v_{C} = \frac{1}{2} v_{P}

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v_{Q} < v_{C} > v_{P}

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Solution

The correct option is A $v_{Q} > v_{C} > v_{P}$
We can take the point in contact with the ground as instantaneous axis of rotation.
$v = r ω$ or
$v \propto r$
$r_{Q} > r_{C} > r_{P}$
$∵ v_{Q} > v_{C} > v_{P}$ .

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A disc is rolling without slipping on a horizontal surface with C, as its centre, and Q and P the two points equidistant from C. Let vP,vQ and vC be the magnitudes of velocities of points P, Q and C respectively, then

The correct option is A vQ>vC>vPWe can take the point in contact with the ground as instantaneous axis of rotation. v=r ω or v∝r rQ>rC>rP ∵vQ>vC>vP.

A disc is rolling without slipping on a horizontal surface with C, as its centre, and Q and P the two points equidistant from
C. Let $v_{P}, v_{Q}$ and $v_{C}$ be the magnitudes of velocities of points $P$ , $Q$ and $C$ respectively, then

The correct option is A $v_{Q} > v_{C} > v_{P}$
We can take the point in contact with the ground as instantaneous axis of rotation.
$v = r ω$ or
$v \propto r$
$r_{Q} > r_{C} > r_{P}$
$∵ v_{Q} > v_{C} > v_{P}$ .