A disc is rolling without slipping with angular velocity - P and Q are two points equidistant from the centre C- The order of magnitude of velocity is-

The correct option is A V_Q > V_C > V_P V _ Q gt; V _ C (As V _ Q is resultant of V _ r and dw) V _ Q gt; V _ P ⇒ V _ Q gt; ...

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Byju's Answer

Standard XII

Physics

Relation between Linear and Angular Speed

A disc is rol...

Question

A disc is rolling without slipping with angular velocity $ω . P$ and $Q$ are two points equidistant from the centre $C$ . The order of magnitude of velocity is:

V_{Q} > V_{C} > V_{P}

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V_{P} > V_{C} > V_{Q}

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V_{Q} = V_{P}, V_{C} = V_{P} / 2

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V_{P} < V_{C} > V_{Q}

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Solution

The correct option is A $V_{Q} > V_{C} > V_{P}$
$V_{Q} > V_{C}$ (As $V_{Q}$ is resultant of $V_{r}$ and dw)
$V_{Q} > V_{P} \Rightarrow V_{Q} > V_{C} > V_{P}$
Therefore, option (A) $V_{Q} > V_{C} > V_{P}$ is correct.

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A disc is rolling without slipping with angular velocity ω.P and Q are two points equidistant from the centre C. The order of magnitude of velocity is:

The correct option is A VQ>VC>VPVQ>VC (As VQ is resultant of Vr and dw)VQ>VP⇒VQ>VC>VPTherefore, option (A) VQ>VC>VP is correct.

A disc is rolling without slipping with angular velocity $ω . P$ and $Q$ are two points equidistant from the centre $C$ . The order of magnitude of velocity is:

The correct option is A $V_{Q} > V_{C} > V_{P}$
$V_{Q} > V_{C}$ (As $V_{Q}$ is resultant of $V_{r}$ and dw)
$V_{Q} > V_{P} \Rightarrow V_{Q} > V_{C} > V_{P}$
Therefore, option (A) $V_{Q} > V_{C} > V_{P}$ is correct.