A disc of mass 5kg and radius 50cm rolls on the ground with a velocity of 10m/s . Calculate the kinetic energy of disc ( I= MR2/2)
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Solution
Given :
mass=m=5kg radius=r=50cm=50 / 100=0.5m Velocity=v=10m/s Moment of Inertia of Disk (M.I) =(1/2)mr² =(1/2)x5 x0.5x0.5 =0.625kgm² Total Kinetic energy =(1/2) I ω² +1/2 mV² =1/2 I (V/r)² + 1/2 m v² =1/2 x 0.625x(10/0.5)² + 1/2 x 5 x 10² =125+ 250 =375J Therefore, Total Kinetic energy is 375 J