1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A disc of radius 'R' and thickness R6 has moment of inertia 'I' about an axis passing through its centre and perpendicular to its plane. Disc is melted and recast into a solid sphere. The moment of inertia of a sphere about its diameter is

A
I5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
I6
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
I32
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
I64
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is A I5Moment of Inertia (MI) of disc is I=MR22..................(1)MI of Solid sphere =25MR2Volumedisc=Volumesolidsphereπ×R2×r6=43π×R′3this will give R′=R2MI of Solid sphere =25M×(R2)2 =MR210or from (1): MISolidSphere=I5

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Moment of Inertia of Solid Bodies
PHYSICS
Watch in App
Join BYJU'S Learning Program