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Byju's Answer
Standard XII
Mathematics
Sample Space
A discrete ra...
Question
A discrete random variable X has the following probability distribution:
X: 1 2 3 4 5 6 7
P(X): c 2c 2c 3c c
2
2c
2
7c
2
+c
Then, P(X ≤ 2) = ____________.
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Solution
For a discrete random variable X
X
P(X)
1
c
2
2c
3
2c
4
3c
5
c
2
6
2
c
2
7
7c
2
+ c
Since
∑
i
=
1
7
p
x
i
=
1
i
.
e
.
c
+
2
c
+
2
c
+
3
c
+
c
2
+
2
c
2
+
7
c
2
+
c
=
1
i
.
e
.
8
c
+
c
+
10
c
2
=
1
i
.
e
.
10
c
2
+
9
c
-
1
=
0
i
.
e
.
10
c
2
+
10
c
-
c
-
1
=
0
i
.
e
.
10
c
c
+
1
-
1
c
+
1
=
0
i
.
e
.
c
=
1
10
∴
P
X
≤
2
=
c
+
2
c
=
2
c
+
c
=
3
c
=
3
×
1
10
i
.
e
P
X
≤
2
=
3
10
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