A discrete random variable X has the probability distribution as given below
X0.511.52P(X)kk22k2k
Determine the mean of the distribution.
We have,
X0.511.52P(X)kk22k2k
Mean of the distribution (μ)=E(X)=∑ni=1ixiPi
0.5(k)+1(k2)+1.5(2k2)+2(k)=4k2+2.5k
=4.19+2.5.13 [∵k=13]
=4+7.59=2318