A dishonest dealer professes to sell his goods at cost price. But he uses a false weight and thus gains $6 \frac{18}{47} %$ . For a kg, he uses a weight of

940

gms

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947

gms

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953

gms

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960

gms

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Solution

The correct option is D $940$ gms
Let error = x gms.

Then, $\frac{x}{1000 - x} \times 100 = 6 \frac{18}{47}$

$=> \frac{100 x}{1000 - x} = \frac{300}{47}$

$=> 100 x \times 47 = 300000 - 300 x$

$=> 4700 x + 300 x = 300000$

$=> x = \frac{300000}{5000}$

$=> x = 60$ gms

Thus, the dealer uses a weight of $(1000 - 60) g m s = 940 g m s$

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A dishonest dealer professes to sell his goods at cost price. But he uses a false weight and thus gains 61847%. For a kg, he uses a weight of

The correct option is D 940 gmsLet error = x gms. Then, x1000−x×100=61847 =>100x1000−x=30047 =>100x×47=300000−300x =>4700x+300x=300000 =>x=3000005000 =>x=60gms Thus, the dealer uses a weight of (1000−60)gms=940gms

A dishonest dealer professes to sell his goods at cost price. But he uses a false weight and thus gains $6 \frac{18}{47} %$ . For a kg, he uses a weight of