Question

A dishonest shopkeeper uses $990g$ weight instead of $1kg$. Neha went to the shopkeeper and asked him to give $5/2kg$ sugar. Fraction of sugar was she cheated of is $\frac{1}{100}$
If true then enter $1$ and if false then enter $0$

Answer 1

The weight of sugar given less is directly
proportional to the weight of the sugar bought.
For $1kg$ sugar, $10g$ of sugar is given less.
Let $a$ grams be the sugar given less for $\frac{5}{2}kg$.

So, $=>1:\frac{5}{2}=10:a$

Applying the rule, product of
extremes $=$ product of means

$1\times a=\frac{5}{2}\times 10$

$a=25grams$ or $\frac{1}{40}$ kg

Hence, the fraction of sugar, she was cheated of $\frac{\frac{1}{40}}{\frac{5}{2}}=\frac{1}{100}$