Question

A disk is rotating with angular velocity $2\pi$ rad/s. Calculate the centripetal acceleration of a point on the edge of this disk if diameter of the disk is 0.20 meter.

• A. 0.04$\pi m/s^2$
• B. 0.20$\pi m/s^2$
• C. 0.16${\pi }^{2}m/s^2$
• D. 0.40${\pi }^{2}m/s^2$
• E. 0.80${\pi }^{2}m/s^2$

Answer 1

Answer: (D)

0.40${\pi }^{2}m/s^2$

Given : $w=2\pi$ rad/s

Diameter of the disk $D=0.2$ m

$\therefore$ Radius of the disk $R=\frac{0.2}{2}=0.1$ m

Centripetal acceleration $a_r=R{w}^2=0.1\times (2\pi {)}^2=0.4{\pi }^2$ $m/s^2$