Question

A disk rotates with 6000 RPM. there are 100 sectors on one track The data transfer speed of the disk is ____________ MBPS, if one track capacity is 1000 bytes.

Answer 1

option (a)

6000 rotations time = 1 minutes = 60sec
$\text{1 rotation time}=\frac{60sec}{6000}=0.01sec$

1 track capaciry = 100 * 1000 Bytes

In rotation one track can be transferred

In 0.01 sec data transferred = 100* 1000 Bytes

$\text{In 1 sec data transferred}=\frac{100{}^{\ast }1000bytes}{0.01sec}$

$=10{}^{\ast }{10}^{6}bytes/sec$

$=10Mbytes/sec$