A- 1 -1 1 2 1 -3 1 1 1 and 10 B- 4 2 2 -5 0 - 1 -2 3 If B is the inverse of matrix A then A then - is

The correct option is A 5 B=A^ 1⇒ AB=1 Hence product of 2 ^nd row and 3 ^rd column =0 1/10 1 amp; 1 amp;1 #160; 2 ...

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Adjoint of a Matrix

A= 1 -1 1...

Question

A= $∣ ∣ ∣ ∣ \begin{matrix} 1 & - 1 & 1 2 & 1 & - 3 1 & 1 & 1 \end{matrix} ∣ ∣ ∣ ∣$ and 10 B= $∣ ∣ ∣ ∣ \begin{matrix} 4 & 2 & 2 - 5 & 0 & α 1 & - 2 & 3 \end{matrix} ∣ ∣ ∣ ∣$ If B is the inverse of matrix A then A then $α$ is____

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A = ⎡ ⎢ ⎣ \begin{matrix} 1 & - 1 & 1 2 & 1 & - 3 1 & 1 & 1 \end{matrix} ⎤ ⎥ ⎦

10 B = ⎡ ⎢ ⎣ \begin{matrix} 4 & 2 & 2 - 5 & 0 & α 1 & - 2 & 3 \end{matrix} ⎤ ⎥ ⎦

α

A =

∣ ∣ ∣ ∣ \begin{matrix} 1 & - 1 & 1 2 & 1 & - 3 1 & 1 & 1 \end{matrix} ∣ ∣ ∣ ∣

10

B =

∣ ∣ ∣ ∣ \begin{matrix} 4 & 2 & 2 - 5 & 0 & α 1 & - 2 & 3 \end{matrix} ∣ ∣ ∣ ∣

B

A

α

⎡ ⎢ ⎣ \begin{matrix} 1 & - 1 & 1 2 & 1 & - 3 1 & 1 & 1 \end{matrix} ⎤ ⎥ ⎦

⎡ ⎢ ⎣ \begin{matrix} 4 & 2 & 2 - 5 & 0 & α 1 & - 2 & 3 \end{matrix} ⎤ ⎥ ⎦

α

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & - 1 & 1 2 & 1 & - 3 1 & 1 & 1 \end{matrix} ⎤ ⎥ ⎦

10 B = ⎡ ⎢ ⎣ \begin{matrix} 4 & 2 & 2 - 5 & 0 & α 1 & - 2 & 3 \end{matrix} ⎤ ⎥ ⎦

α

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & - 1 & 1 2 & 1 & - 3 1 & 1 & 1 \end{matrix} ⎤ ⎥ ⎦

10 B = ⎡ ⎢ ⎣ \begin{matrix} 4 & 2 & 2 - 5 & 0 & α 1 & - 2 & 3 \end{matrix} ⎤ ⎥ ⎦

B

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α

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