Question

A divalent metal with atomic number $12$ reacts with an acid liberating a gas $X$. $X$ on treatment with a non metal $Y$ gives $Z$, which on dissolution in water produces the same acid. Identify $X,Y$ and $Z$.

• A. ${Cl}_2,H_2,HCl$
• B. $H_2,HCl,{Cl}_2$
• C. $HCl,H_2,{Cl}_2$
• D. $H_2,{Cl}_2,HCl$

Answer 1

Answer: (D)

$H_2,{Cl}_2,HCl$

A divalent metal with atomic number $12$ is $Mg$ ,
reacts with an acid liberating a gas $X$. $Mg+HCl\to MgC{l}_2+{H_2}_{\left(g\right)}$.
$X$ is gas $H_2$. $H_2$ on treatment with a non metal $C{l}_2$ gives $HCl$, which on dissolution in water produces the same acid $HCl$.$Y$ is $C{l}_2$ and $Z$ is $HCl$.
$H_2+C{l}_2\to HCl$
$C{l}_2+H_{2}O\to 2HCl+O_2$