Question

A diver at a depth of 12m in water ($\mu$ = $\frac{4}{3}$ ) sees the sky in a cone of semi-vertical angle

• A. sin^-1 (4/3)
• B. tan^-1 (4/3)
• C. sin^-1 (3/4)
• D. 90°

Answer 1

The correct option is C sin^-1 (3/4)

Semi vertical angle = c

$si{n}^{-1}\left(\frac{1}{\mu }\right)=si{n}^{-1}\left(\frac{3}{4}\right)$