A diver at a depth of 12m in water sees the sky in a cone of semi vertical angle a) sin^-1(4/3) b) tan^-1(4/3) c) sin^-1(3/4) d) 90degrees

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(μ = \frac{4}{3})

A diver at a depth of 12m in water ( $μ$ = $\frac{4}{3}$ ) sees the sky in a cone of semi-vertical angle

12 m

(μ = \frac{4}{3})

\int {sin}^{13} x {cos}^{3} x d x = A {sin}^{14} x + B {sin}^{16} x + C

A + B =

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