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Question

A diver makes 4 revolutions on the way from a 4.9 m platform above the water surface. Assuming zero initial vertical velocity, calculate the average angular velocity of the diver. [Take g=9.8 m/s2]

A
8π rad/s
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B
4π rad/s
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C
2π rad/s
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D
π rad/s
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Solution

The correct option is A 8π rad/s
We know that the average angular velocity is given by
¯ω=ΔθΔt
Since the diver makes four revolutions, the angular displacement of the diver is Δθ=4×2π=8π rad

Now, as the dimension of the diver is not mentioned here, we can consider it as a small particle falling freely under gravity.
Time taken to fall is
Δt=2hg=2×4.99.8=1 sec
Thus, average angular velocity is
¯ω=ΔθΔt=8π1=8π rad/s

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