A diver reaches a depth of $300 m$ . The pressure (in atm) exerted by water at that depth is $2.94 \times 10^{x} .$ (in Pascal). Take $g = 9.8 m / s^{2}$ . Find x.

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Solution

height = 300m
Hydrostatic pressure = $ϱ g h$
= $1000 \frac{k g}{m^{3}} \times 9.8 \frac{m}{s^{2}} \times 300 m$
Hydrostatic pressure = $2.94 \times 10^{6} P a s c a l$

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A diver reaches a depth of 300m. The pressure (in atm) exerted by water at that depth is 2.94×10x. (in Pascal). Take g=9.8m/s2 . Find x.

height = 300mHydrostatic pressure = ϱgh = 1000kgm3×9.8ms2×300mHydrostatic pressure = 2.94×106Pascal

A diver reaches a depth of $300 m$ . The pressure (in atm) exerted by water at that depth is $2.94 \times 10^{x} .$ (in Pascal). Take $g = 9.8 m / s^{2}$ . Find x.

height = 300m
Hydrostatic pressure = $ϱ g h$
= $1000 \frac{k g}{m^{3}} \times 9.8 \frac{m}{s^{2}} \times 300 m$
Hydrostatic pressure = $2.94 \times 10^{6} P a s c a l$