A diverging lens has a focal length of 0.10 m. The power of this lens will be : (a) + 10.0 D (b) + 1.0 D (c) - 1.0 D (d) - 10.0 D

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Solution

(d)

$P o w e r o f l e n s = \frac{1}{f o c a l l e n g t h} = \frac{1}{- 10} = - 10 D$

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A diverging lens has a focal length of 0.10 m. The power of this lens will be : (a) + 10.0 D (b) + 1.0 D (c) - 1.0 D (d) - 10.0 D

(d) Power of lens=1focal length=1−10=−10 D

(d)

$P o w e r o f l e n s = \frac{1}{f o c a l l e n g t h} = \frac{1}{- 10} = - 10 D$