A diverging lens has a focal length of 0.10 m. The power of this lens will be :
(a) +10.0D
(b) +1.0D
(c) −1.0D
(d) −10.0D

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Solution

(d) -10.0D,
since power of lens = $\frac{1}{focal length} = \frac{1}{- 0.10} = - 10.0 D$ .

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A diverging lens has a focal length of 0.10 m. The power of this lens will be : (a) +10.0D (b) +1.0D (c) −1.0D (d) −10.0D

(d) -10.0D, since power of lens = 1focal length=1-0.10=-10.0 D.

A diverging lens has a focal length of 0.10 m. The power of this lens will be :
(a) +10.0D
(b) +1.0D
(c) −1.0D
(d) −10.0D

(d) -10.0D,
since power of lens = $\frac{1}{focal length} = \frac{1}{- 0.10} = - 10.0 D$ .