A diverging lens with magnitude of focal length 25cm is placed at a distance of 15cm from a converging lens of magnitude of focal length 20cm. A beam of parallel light falls on the diverging lens. The final image formed is
A
Real and at a distance of 6cm from the convergent lens.
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B
Real and at a distance of 40cm from the convergent lens.
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C
Virtual and at a distance of 40cm from the convergent lens.
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D
Real and at a distance of 40cm from the divergent lens.
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Solution
The correct option is B Real and at a distance of 40cm from the convergent lens. For concave lens,
1f1=1V1−1u1
⇒−125=1V1−1∞
⇒V1=−25cm
This image acts as an object for convex lens placed at 40cm from its principle axis.