A diwali rocket is ejecting 0.05 kg of gases per second at a velocity of 400 m/sec. The accelerating force on the rocket is

20 dynes

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20 N

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22 dynes

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1000 N

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Solution

The correct option is B
20 N

$F = u (\frac{d m}{d t}) = 400 \times 0.05 = 20 N$

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