A Diwali rocket is ejecting 0.05 kg of gases per second at a velocity of $400 {m s}^{- 1}$ . The accelerating force on the rocket is equal to :

20 dyne

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 newton

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

20 kg wt

No worries! We‘ve got your back. Try BYJU‘S free classes today!

sufficient data not given

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 20 newton
Accelerating force on the rocket $F = V \frac{d m}{d t}$
$⟹ F = 400 \times 0.05 = 20 N$

Suggest Corrections

Similar questions

0.05 k g

400 m s^{- 1}

A diwali rocket is ejecting 0.05 kg of gases per second at a velocity of 400 m/sec. The accelerating force on the rocket is

A cracker rocket is ejecting gases at a rate of 0.05kg/s with a velocity 400 m/s. What will be the accelerating force on the rocket?

Join BYJU'S Learning Program