A does a work in 10 days and B does the same work in 15 days. In how many days will they together finish the same work?

5 days

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6 days

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8 days

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9 days

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7 days

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Solution

The correct option is B
6 days

A’s 1 day’s work = $\frac{1}{10}$ and B’s 1 day’s work = $\frac{1}{15}$

$∴$ (A+B)’s 1 day’s work = $(\frac{1}{10} + \frac{1}{15}) = \frac{1}{6}$

So, both together will finish the work in 6 days.

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Similar questions

A alone can do a piece of work in 10 days and B alone can do it in 15 days. In how many days will A and B together do the same work?

(a) 5 days

(b) 6 days

(d) 9 days

Q. Tick (✓) the correct answer:
A alone can do a piece of work in 10 days and B alone can do it in 15 days. In how many days will A and B together do the same work?
(a) 5 days
(b) 6 days
(c) 8 days
(d) 9 days

Q. A does a work in

10

days and B does the same work in

15

days. In how many days they together will do the same work.

X and Y together can complete a work in 6 days. X alone can complete it in 10 days. If Y does the work only for half a day daily, then in how many days will X and Y together complete the work?

X and Y together can finish a work in 15 days. They worked on it for 10 days and then Y left. The remaining work was done by X alone in 15 days. In how many days can X alone finish the work?

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A does a work in 10 days and B does the same work in 15 days. In how many days will they together finish the same work?

The correct option is B 6 days A’s 1 day’s work = 110 and B’s 1 day’s work = 115 ∴ (A+B)’s 1 day’s work = (110 + 115) = 16 So, both together will finish the work in 6 days.

The correct option is B
6 days

A’s 1 day’s work = $\frac{1}{10}$ and B’s 1 day’s work = $\frac{1}{15}$

$∴$ (A+B)’s 1 day’s work = $(\frac{1}{10} + \frac{1}{15}) = \frac{1}{6}$

So, both together will finish the work in 6 days.