A domestic electric circuit has a fuse of $5 A$ . What is the maximum number of $100 W (220 V)$ bulbs that can be safely used in the circuit?

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Solution

Power (P)= $v o l t a g e (v) \times c u r r e n t (i) = 100 W$
$i =$ $\frac{100}{220} = 0.45 A$
Number of bulbs that can be safely operated through a $5 A$ fuse $=$ $\frac{5}{0.45}$ $= 11$

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A domestic electric circuit has a fuse of 5A. What is the maximum number of 100W(220V) bulbs that can be safely used in the circuit?

Power (P)= voltage(v)×current(i)=100Wi=100220=0.45ANumber of bulbs that can be safely operated through a 5A fuse =50.45=11

A domestic electric circuit has a fuse of $5 A$ . What is the maximum number of $100 W (220 V)$ bulbs that can be safely used in the circuit?

Power (P)= $v o l t a g e (v) \times c u r r e n t (i) = 100 W$
$i =$ $\frac{100}{220} = 0.45 A$
Number of bulbs that can be safely operated through a $5 A$ fuse $=$ $\frac{5}{0.45}$ $= 11$