A domestic lighting circuit has a fuse of 5A. If the main supply is at 230V. Calculate the maximum number of 36W tube-lights that can be safely used in this circuit.
A
22
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B
31
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C
47
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D
12
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Solution
The correct option is B31 Let the maximum number of tube - lights that can be used safely is N.
Power consumed by N tube lights is,
P=36N
The maximum power that can be drawn is,
Pmax=230×5=1150
So,
36N=1150
⇒N=115036=31.94
Therefore, the maximum number of tube lights that can be used are 31.