wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A domestic lighting circuit has a fuse of 5 A. If the main supply is at 230 V. Calculate the maximum number of 36 W tube-lights that can be safely used in this circuit.

A
22
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
31
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
47
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 31
Let the maximum number of tube - lights that can be used safely is N.

Power consumed by N tube lights is,

P=36N

The maximum power that can be drawn is,

Pmax=230×5=1150

So,

36N=1150

N=115036=31.94

Therefore, the maximum number of tube lights that can be used are 31.

Hence, option (B) is the correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fuse 
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon