Question

A door is in the shape of a rectangle surmounted by a semicircle. If the width of the door is $4$ it and the height of the door is $10.25$ it find the total area of the door.

Answer 1

Given width of door =4.

height of door =10.25.

and door is surmounted by a semicircle or radius =2.

Total area of door =area of rectangle +area of semicircle

$-lb+\pi r^2/2$

$=4\times 10.25+6.+\frac{(2{)}^2\times 3.14}{2}$

=41.00+6.28

[Total area of door =47.28 sq.unit]