Question

A door is pushed open by applying a force of 50 N at a point 50 cm from the hinges. What is the moment of the force?

• A. 0.25 Nm
• B. 2.5 Nm
• C. 25 Nm
• D. 2500 Nm

Answer 1

The correct option is C

25 Nm

Step-1: Given data

Perpendicular Distance, $d=50cm=\frac{50}{100}m=0.5m$

Force, $F=50N$

Step-2: Finding the moment of force

The moment of force is defined by the product of force and the perpendicular distance from the pivot.

$i.e.momentofforce=F\times d=50\times 0.5=25Nm$

The moment of force is $25Nm.$

Hence, option C is correct.