Question

A double beam CRO has a bandwidth of $10MHz$. Two signals
$V_1\left(t\right)=10sin(2\pi \times 20\times {10}^{3}t)$ and
$V_2\left(t\right)=10sin(2\pi \times 20\times {10}^{6}t)$ are applied to the two channels. If $P_{1}and{P}_2$ are the peak-to-peak values of the signals displayed, then

• A. $P_1=20,P_2=20$
• B. $P_1<20,P_2>20$
• C. $P_1=20,P_2<20$
• D. $P_1>20,P_2<20$

Answer 1

The correct option is A $P_1=20,P_2=20$

$GivenbandwidthofCRO=10MHz$

$andfrequencyof{V}_1=20kHz$
$andfrequencyof{V}_2=20MHz$

So, CRO passes $V_1$ as it is but compressses $V_2$.

This compression in $V_2$ do not effect peak values and hence peak to peak value will be unchanged. For $V_1$, peak to peak value is
$P_1=10-(-10)=20V$

$Similarlyfor{V}_2$,
$peaktopeakvalue=20V$