A double convex lens- made of a material of refractive index -1- is placed inside two liquids of refractive indices mu2 and -3 as shown- mu2 - mu1 - mu3- A wide- parallel beam of light is incident on the lens from the left- The lens will give rise to

The correct option is D a convergent and a divergent beam.As μ_2 gt; μ_1 the upper half of the lens will becoming #10;diverging. And the lower ha ...

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Standard XII

Physics

Refractive Index

A double conv...

Question

A double convex lens, made of a material of refractive index $μ_{1}$ , is placed inside two liquids of refractive indices $m u_{2} a n d μ_{3}$ as shown. $m u_{2} > m u_{1} > m u_{3}$ . A wide, parallel beam of light is incident on the lens from the left. The lens will give rise to

a single convergent beam

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two different convergent beams

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two different divergent beams

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a convergent and a divergent beam.

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Solution

The correct option is D a convergent and a divergent beam.
As $μ_{2} > μ_{1}$ the upper half of the lens will becoming diverging. And the lower half of the lens will becoming converging.

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A double convex lens, made of a material of refractive index μ1, is placed inside two liquids of refractive indices mu2andμ3 as shown. mu2>mu1>mu3. A wide, parallel beam of light is incident on the lens from the left. The lens will give rise to

The correct option is D a convergent and a divergent beam.As μ2>μ1 the upper half of the lens will becoming diverging. And the lower half of the lens will becoming converging.

A double convex lens, made of a material of refractive index $μ_{1}$ , is placed inside two liquids of refractive indices $m u_{2} a n d μ_{3}$ as shown. $m u_{2} > m u_{1} > m u_{3}$ . A wide, parallel beam of light is incident on the lens from the left. The lens will give rise to

The correct option is D a convergent and a divergent beam.
As $μ_{2} > μ_{1}$ the upper half of the lens will becoming diverging. And the lower half of the lens will becoming converging.