Question

A double cover butt riveted joint is used to connect two flat plates of 200 mm width and 14 mm thickness as shown in the figure. There are twelve power driven rivets of 20 mm diameter at a pitch of 50 mm in both directions on either side of the plate. Two cover plates of 10 mm thickness are used. The capacity of the joint in tension considering bearing and shear only, with permissible bearing and shear stresses as 300 MPa and 100 MPa respectively is _________.

• A. 871.32 kN
• B. 541.8 kN
• C. 433.7 kN
• D. 1083.6 kN

Answer 1

The correct option is A 871.32 kN

Nominal dia of rivet,
d = 20 mm
Gross dia of rivet
d' = d + 1.5
= 21.5 mm



Rivets are in double shear,
Strength of rivet in shearing

$=\frac{2\pi \times d^{\prime 2}}{4}\times 100$
$=2\times \pi \times \frac{(21.5{)}^2}{4}\times 100N$
= 72.61 kN

Strength of rivet in bearing
= (d' x t) x permissible bearing stress
= (21.5 x 14) x 300
= 90.3 kN

Given, consider failure of joint in shearing and bearing only

Rivet value = Min (strength of rivet in shearing and bearing) = 72.61 kN

Capacity of joint = Rivet value x number of rivet = 72.61 x 12 = 871.32 kN.