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Question

A double slit experiment is performed with light of wavelength 500 nm.  A thin film of thickness 2μ m and refractive index 1.5 is introduced in the path of the upper beam.  The location of the central maximum will:
  1. Remain unshifted
  2. Shift downward by nearly two fringes
  3. Shift upward by nearly two fringes           
  4. Shift downward by 10 fringes


Solution

The correct option is C Shift upward by nearly two fringes           
Shift=Dd(μ1)t=Dd[1.51]×2×106=Dd×106
Now, fringe width ω=Dd×500×109
shiftω=Dd×106Dd×5×107=2
 shift=2ω, since the film is kept in the path of upper beam, the shift will be upward.

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