Question

A double slit is illuminated by light of wave length 6000$A^0$.The slits are 0.1 cm apart and the screen is placed 1 m away. Then the angular position of 10th maxima is

• A. $6\times {10}^{-3}rad$
• B. 6 rad
• C. ${0.006}^{\circ }$
• D. $6^0$

Answer 1

The correct option is B 6 rad

$\begin{array}{c}\lambda =6000A^o\\ d=0.1cm\\ D=1\\ angular=\frac{10\beta }{D}\\ =\frac{10\times \lambda D}{dD}=\frac{10\lambda }{d}=\frac{10\times 6000\times {10}^{-10}\times 100}{o.1}\\ =6\times {10}^{-3}\\ =6rad\\ Hence,\\ optionBiscorrectanswer.\end{array}$