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Question

A double slit is illuminated by light of wavelength 6000 A. The slits are 0.1 cm apart and the screen is placed one meter away. Then the angular position of the 10th maximum in radian and separation of the two adjacent minima will be respectively

A
6×103 rad, 0.6 mm
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B
3×103 rad, 0.3 mm
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C
2×103 rad, 0.2 mm
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D
4×103 rad, 0.4 mm
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Solution

The correct option is A 6×103 rad, 0.6 mm

Distance of nth maximum from centre
y=nλDd

So, angular position of nth maximum
θ=yD=nλd (small angle approximation)

So for n=10, θn=10×6000×10100.001=6×103 rad

Separation between two adjacent minima = separation between two adjacent maxima = fringe width
β=λDd=6000×1010×10.001=6×104 m=0.6 mm

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