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Question
A double stranded DNA molecule of length 3.4 mm has 30000 cytosine, then calculate the total number of thymine nucleotides present in DNA?
A double stranded DNA molecule of length 3.4 mm has 30000 cytosine, then calculate the total number of thymine nucleotides present in DNA?
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Solution
The correct option is D 470000
The complementary base pairing in DNA helix proves Chargaff's rule. The content of adenine equals that of thymine (A=T) and guanine equals that of cytosine (G=T).A turn of a DNA helix which is 3.4 nm contains 10 base pairs.3.4 mm = 3.4 * 10^6 nm3.4 nm of DNA contains 10 base pairs. So 3.4 mm of DNA contains 10^6 basepairs.It is given that the number of cytosine = 30000. Therefore, by cChargaff's rule, the number of guanines is 30000.The amount of adenine and thymine = total number of base pairs - total number of guanine and cytosine = 10^6 - 60000 = 940000.Hence, A + T = 940000.Number of thymine = 940000 / 2 =470000.Thus, the correct answer is '470000.'
The complementary base pairing in DNA helix proves Chargaff's rule. The content of adenine equals that of thymine (A=T) and guanine equals that of cytosine (G=T).
A turn of a DNA helix which is 3.4 nm contains 10 base pairs.
3.4 mm = 3.4 * 10^6 nm
3.4 nm of DNA contains 10 base pairs. So 3.4 mm of DNA contains 10^6 basepairs.
It is given that the number of cytosine = 30000. Therefore, by cChargaff's rule,
the number of guanines is 30000.
The amount of adenine and thymine = total number of base pairs - total number of guanine and cytosine = 10^6 - 60000 = 940000.
Hence, A + T = 940000.
Number of thymine = 940000 / 2 =470000.
Thus, the correct answer is '470000.'
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