Question

a. Draw the given diagram and label the following in the diagram.
i) Incident ray
ii) Refracted ray
iii) Emergent ray
iv) Angle of refraction
v) Angle of deviation
vi) Angle of emergence
b. The refractive index of diamond is 2.42. What is the meaning of this statement in relation to the speed of light?

Answer 1

Given: Refractive index of diamond is $2.42$

Solution:

We know , $\mu =\frac{c}{v}$

Hence,

$\text{Refractive index of diamond}=\frac{\text{Speed of light in air}}{\text{Speed of light in diamond}}⟹\text{Speed of light in air}=2.42\times \text{Speed of light in diamond}$

This means the speed of light in air is $2.42$ times the speed of light in diamond.