Question

(a)

Draw the structures for the following compound: ​
(i) Ethanoic acid

(b)
(ii) Bromopentane

(c)
(iii) Butanone

(d)
(iv) Hexanal

(e)
Are structural isomers possible for bromopentane?

Answer 1

(a)
The molecular formula of ethanoic acid is $C{H}_{3}COOH$. Its molecular structure is:

(b)
The molecular formula of bromopentane is $C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}C{H}_{2}Br.$ Its molecular structure is:


(c)
The molecular formula of Butanone is $C{H}_{3}COC{H}_{2}C{H}_3.$Its molecular structure is:


(d)
The molecular formula of hexanal is $C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}C{H}_{2}CHO.$ Its molecular structure is:


(e)

Yes, structural isomers for bromopentane are possible.​

Isomers of bromopentane are: ​

• 1-Bromopentane​

• 2-Bromopentane​

• 3-Bromopentane​

• 1-Bromo-2-methylbutane​

• 1-Bromo-2,2-dimethylpropane​

• 2-Bromo-2-methylbutane​

• 2-Bromo-3-methylbutane​

• 1-Bromo-3-methylbutane