A drawing pin is pierced in a wooden table with a force of 5N.Calculate the pressure exerted by the pin on the wooden table if the area is 0.02mm

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Solution

Force excerpted , F= 5N

Applied area ,
A= .02 mm^2
A= .02 × (10^-6) m^2

Pressure , P= F/A
P=5/(.02 × (10^-6))
P=250×10^6

P=250000000 N/m

Therefore pressure applied = 250000000 N/m

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A drawing pin is pierced in a wooden table with a force of 5N.Calculate the pressure exerted by the pin on the wooden table if the area is 0.02mm

Force excerpted , F= 5N ​​​​​​ Applied area , A= .02 mm^2 A= .02 × (10^-6) m^2 Pressure , P= F/A P=5/(.02 × (10^-6)) P=250×10^6 P=250000000 N/m Therefore pressure applied = 250000000 N/m

Force excerpted , F= 5N

Applied area ,
A= .02 mm^2
A= .02 × (10^-6) m^2

Pressure , P= F/A
P=5/(.02 × (10^-6))
P=250×10^6

P=250000000 N/m

Therefore pressure applied = 250000000 N/m