Question

A drink vendor has 80 liters of Maaza 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans so that each can contains the same number of liters of a drink and doesn't want to mix any two drinks in a can. What is the least number of cans?

• A. $37$
• B. $48$
• C. $22$
• D. $11$

Answer 1

The correct option is A $37$

Volume of maaza$=80l$

Volume of pepsi $=144l$

Volume of sprite$=368l$

To get least number of cans ,volume of a can should be maximum.

volume of one can$=HCF(80,144and368)$

$=16$

Number of cans of maaza$=\frac{80}{16}$

$=5$

Number of cans of pepsi$=\frac{144}{16}$

$=9$

Number of cans of sprite$=\frac{368}{16}$

$=23$

Total number of cans $=5+9+23$

$=37$