Question

A drinking glass is in the shape of a frustum of a cone of height 14 cm. The diameter of its two circular ends are 4 cm and 2 cm. The capacity of the glass is $102\frac{2}{3}c{m}^3$.

• A.
• B.

Answer 1

The correct option is A

Height of frustum of cone = h = 14 cm

Radius of one end = $r_1=1$ cm

Radius of the other end = $r_2=2$ cm

Volume of frustum of cone =
$\frac{1}{3}$ $\pi .h\left(\right(r_1{)}^2+(r_2{)}^2+(r_1\left)\right(r_2\left)\right)$

$=\frac{1}{3}\times \frac{22}{7}\times 14(1^2+2^2+(1\left)\right(2\left)\right)$

$=\frac{1}{3}\times \frac{22}{7}\times 14\times 7=\frac{308}{3}=102\frac{2}{3}c{m}^3$