A driver charges ₹40 for a distance of 8 km, then match the following amount with their distance.

16 km

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4 km

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40 km

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32 km

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Solution

We know that the driver charges and the distance are directly related.

$S o, \frac{D r i v e r C h a r g e s}{D i s t a n c e} = c o n s t a n t$

$\frac{40}{8} = 5 = c o n s t a n t$

Let the distance to be travelled be x km.

$S o, \frac{20}{x} = \frac{40}{8}$
$\frac{20}{x} = 5 \Rightarrow x = 4 k m$

Similarly,
$\frac{80}{x} = 5 \Rightarrow x = 16 k m$

$\frac{160}{x} = 5 \Rightarrow x = 32 k m$

$\frac{200}{x} = 5 \Rightarrow x = 40 k m$

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The taxi charges in a city consist of a fixed $2 M$ charge together with the charge for the distance covered. For a distance of $10 k m$ , the charge paid is $R s 105$ & for a journey of $15 k m$ the charge paid is $R s 155$ . What is the fixed charges and the charge per $k m$ ? How much does a person have to pay for travelling a distance of $25 k m$ ?

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A driver charges ₹40 for a distance of 8 km, then match the following amount with their distance.

We know that the driver charges and the distance are directly related. So, Driver ChargesDistance = constant 408=5=constant Let the distance to be travelled be x km. So,20x=408 20x=5⇒x=4 km Similarly, 80x=5⇒x=16 km 160x=5⇒x=32 km 200x=5⇒x=40 km