A drop of liquid of diameter 2.8mm break up into 216 identical drops. What is the approximate change in energy of bigger drop?
(Given: Surface tension of liquid, T=75dyne/cm)
A
25πerg
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B
29.4πerg
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C
32πerg
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D
28πerg
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Solution
The correct option is B29.4πerg ⇒Change in energy (energy required) in splitting of bigger drop to n smaller drops is, ΔE=4πR2T(n1/3−1)...(i)
Where, Radius of bigger drop R=1.4×10−1cm n= Number of small drops T= Surface tension
From Eq. (i) we get, ΔE=4×π×(1.4×10−1)2×75(2161/3−1)dyne.cm
Since 1erg=1dyne.cm ∴ΔE=29.4πerg