A drop of solution volume 0-10 mL contains 6-10-6 mole of H- if the rate constant of disappearance of H- is 1-107 mole litre-1 sec-1- How long would it take for H- in drop to disappear-

The correct option is D 6× 10^ 9 sec The hydrogen ion concentration is 6 × 10^ 6× 1000/0.1 =0.06 M The time required to for the protons in the drop t ...

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Standard XII

Chemistry

Degree of Dissociation

A drop of sol...

Question

A drop of solution (volume 0.10 mL) contains $6 \times 10^{- 6}$ mole of $H^{+}$ , if the rate constant of disappearance of $H^{+}$ is $1 \times 10^{7} m o l e l i t r e^{- 1} s e c^{- 1}$ . How long would it take for $H^{+}$ in drop to disappear?

6 \times 10^{- 9} s e c

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3 \times 10^{- 9} s e c

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12 \times 10^{- 9} s e c

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None of these

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Solution

The correct option is D $6 \times 10^{- 9} s e c$
The hydrogen ion concentration is $\frac{6 \times 10^{- 6} \times 1000}{0.1} = 0.06 M$
The time required to for the protons in the drop to disappear
$= \frac{0.06}{1 \times 10^{7}} = 6 \times 10^{- 9} s e c$

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A drop of solution (volume 0.10 mL) contains 6×10−6 mole of H+, if the rate constant of disappearance of H+ is 1×107molelitre−1sec−1. How long would it take for H+ in drop to disappear?

The correct option is D 6×10−9secThe hydrogen ion concentration is 6×10−6×10000.1=0.06MThe time required to for the protons in the drop to disappear =0.061×107=6×10−9sec

A drop of solution (volume 0.10 mL) contains $6 \times 10^{- 6}$ mole of $H^{+}$ , if the rate constant of disappearance of $H^{+}$ is $1 \times 10^{7} m o l e l i t r e^{- 1} s e c^{- 1}$ . How long would it take for $H^{+}$ in drop to disappear?

The correct option is D $6 \times 10^{- 9} s e c$
The hydrogen ion concentration is $\frac{6 \times 10^{- 6} \times 1000}{0.1} = 0.06 M$
The time required to for the protons in the drop to disappear
$= \frac{0.06}{1 \times 10^{7}} = 6 \times 10^{- 9} s e c$