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Surface Tension

A drop of wat...

Question

A drop of water of volume V is pressed between the two glass plates so as to spread to an area A. If T is the surface tension, the normal force required to separate the glass plate is $\frac{k T A^{2}}{V}$ ,then k=___

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Solution

Pressure difference

$\frac{2 T}{R} = \frac{2 T}{t / 2} = \frac{4 T}{t}$
Force $= \frac{4 T}{t} A$
But V = At or t = $\frac{V}{A}$
$∴$ Force= $\frac{4 T A^{2}}{V}$

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