A drum full of rice weighs 401-6kg- If the empty drum weighs 133-4kg- find the weight of rice in the drum-

Total weight of rice and drum = 401/6 kg=241/6 kg Weight of empty drum = 133/4=55/4 kg ∴ Weight of rice =(241/6 55/4 )kg =482 165/12=317/12 kg=265/12 kg Ans. ...

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Standard VII

Mathematics

Subtraction of Rational Numbers

A drum full o...

Question

A drum full of rice weighs $40 \frac{1}{6} k g$ . If the empty drum weighs $13 \frac{3}{4}$ kg, find the weight of rice in the drum.

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Solution

Total weight of rice and drum = $40 \frac{1}{6} k g = \frac{241}{6} k g$

Weight of empty drum = $13 \frac{3}{4} = \frac{55}{4} k g$

$∴$ Weight of rice = $(\frac{241}{6} - \frac{55}{4}) k g$

$= \frac{482 - 165}{12} = \frac{317}{12} k g = 26 \frac{5}{12} k g A n s .$

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A drum full of rice weighs 4016kg. If the empty drum weighs 1334kg, find the weight of rice in the drum.

Total weight of rice and drum = 4016 kg=2416 kg Weight of empty drum = 1334=554 kg ∴ Weight of rice =(2416−554)kg =482−16512=31712 kg=26512 kg Ans.

A drum full of rice weighs $40 \frac{1}{6} k g$ . If the empty drum weighs $13 \frac{3}{4}$ kg, find the weight of rice in the drum.

Total weight of rice and drum = $40 \frac{1}{6} k g = \frac{241}{6} k g$

Weight of empty drum = $13 \frac{3}{4} = \frac{55}{4} k g$

$∴$ Weight of rice = $(\frac{241}{6} - \frac{55}{4}) k g$

$= \frac{482 - 165}{12} = \frac{317}{12} k g = 26 \frac{5}{12} k g A n s .$